Question

Solve the 55 tu question with Proper steps.

Answer 1

Note that only the magnitude of 'g' is being calculated in this way.It's unit remains same as that of acceleration i.e.m/s^2

Answer 2

Hello Mate!

Since we know that,

g = GM/R²

So radius will be = 12.8 × 10³ / 2 km

= 6.4 × 10³ km

But, we have to convert it into m

= 6.4 × 10³ × 10³ = 6.4 × 10^6.

So value of g will be,

$g = \frac{6.7 \times {10}^{ - 11} \times 6 \times {1 0}^{24} }{ {(6.4 \times {10}^{6} )}^{2} } \\ = \frac{6.7 \times 6 \times {10}^{ - 11 + 24} }{6.4 \times 6.4 \times {10}^{12} } \\ = 0.98 \times {10}^{13 - 12} \\ =0 .98 \times 10 = 9.8 \:m {s}^{ - 2}$

No doubt, it is none other than Earth whose gravitational acceleration is 9.8 m/s²

Have great future ahead!