Question

solve the 5th question

Answer 1

Answer:

Step-by-step explanation:

Please do not use implies that

In place of =

Answer 2

Answer:

The answer is 1.

Step-by-step explanation:

Here, the given expression,

$\frac{sin^3\theta + cos^3\theta}{sin \theta + cos\theta}+sin\theta.cos \theta$

$=\frac{(sin\theta + cos\theta)(sin^2\theta-sin \theta cos \theta+ cos^2\theta)}{sin\theta + cos\theta}+sin\theta. cos\theta$

( Because, a³+b³=(a+b)(a²-ab+b²) )

$=sin^2\theta-sin \theta cos \theta+ cos^2\theta+sin\theta. cos\theta$

( Because, sin²x + cos²x = 1 )

$=1-sin\theta.cos\theta + sin\theta.cos\theta$

$=1$