solve the 8, 9, 10 question
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heya friend!!☺☺
here are your answers!!☺☺
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Q.8.➡Speed of the train in the first 30 km, v1 = 30 km/h
Speed of the train in the next 90 km, v2 (to be determined)
Average speed = 60 km/h = (v1 + v2)/2
= (30 km/h + v2)/2
⇒ v2 = 90 km/h
Q.9.➡Average speed = Total distance covered / Total time taken
Time taken to travel the first 40 km = 1 h
Time taken to travel the next 30 km = 30km /(20 km/h) = 1.5 h
Total distance travelled = 40 + 30 = 70 km
Total time taken = 1 + 1.5 = 2.5 h
Average speed = 70 km/ 2.5 h
= 28 km/h
Q.10. ➡Given:-
Velocity = 120m/hr120m/hr
Velocity in m/s is:- 120/3600=0.033m/s120/3600=0.033m/s
Time = 30 seconds.
So, from formula speed=distance/timespeed=distance/time
0.033=distance/300.033=distance/30
Distance=0.033×30mDistance=0.033×30m
Distance=0.99mor( 1m)Distance=0.99mor( 1m)
Therefore, the train will cover 0.99 m (~1 m) in 30 seconds.
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hope it helps you!!☺☺
here are your answers!!☺☺
__________________________________
__________________________________
Q.8.➡Speed of the train in the first 30 km, v1 = 30 km/h
Speed of the train in the next 90 km, v2 (to be determined)
Average speed = 60 km/h = (v1 + v2)/2
= (30 km/h + v2)/2
⇒ v2 = 90 km/h
Q.9.➡Average speed = Total distance covered / Total time taken
Time taken to travel the first 40 km = 1 h
Time taken to travel the next 30 km = 30km /(20 km/h) = 1.5 h
Total distance travelled = 40 + 30 = 70 km
Total time taken = 1 + 1.5 = 2.5 h
Average speed = 70 km/ 2.5 h
= 28 km/h
Q.10. ➡Given:-
Velocity = 120m/hr120m/hr
Velocity in m/s is:- 120/3600=0.033m/s120/3600=0.033m/s
Time = 30 seconds.
So, from formula speed=distance/timespeed=distance/time
0.033=distance/300.033=distance/30
Distance=0.033×30mDistance=0.033×30m
Distance=0.99mor( 1m)Distance=0.99mor( 1m)
Therefore, the train will cover 0.99 m (~1 m) in 30 seconds.
_________________________________
hope it helps you!!☺☺
kingofbasketbll:
yes please
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