solve the above 8th question as directed in statement
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Steph0303:
7 th or 8thh
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Hey Mate !!
Here's your answer !!
Given: AP: 5, 17, 29, 41....
So, a = 5, d = 17 - 5 = 12
So the only way to solve is to add the common difference and find out till
15 th term.
Fifth term = 41 + 12 = 53
Sixth term = 53 + 12 =65
Seventh term = 65 + 12 = 77
Eighth term = 77 + 12 = 89
Ninth term = 89 + 12 = 101
Tenth term = 101 + 12 = 113
Eleventh term = 113 + 12 = 125
Twelfth term = 125 + 12 = 137
Thirteenth term = 137 + 12 = 149
Fourteenth term = 149 + 12 = 161
Fifteenth term = 161 + 12 = 173.
Therefore 15 th term = 173
It is given to find 120 more than the 15 th term. Therefore,
173 + 120 = 293.
So the term's number would be 120 divided by common difference ( d ).
Term = 120 / 12 = 10
So it is the 10 th term after 15th term which is 25 th term.
Hence 293 is the 25 th term of that AP.
Hope this helps !!
Cheers !!
____________________________________________________________
# Kalpesh :)
Hey Mate !!
Here's your answer !!
Given: AP: 5, 17, 29, 41....
So, a = 5, d = 17 - 5 = 12
So the only way to solve is to add the common difference and find out till
15 th term.
Fifth term = 41 + 12 = 53
Sixth term = 53 + 12 =65
Seventh term = 65 + 12 = 77
Eighth term = 77 + 12 = 89
Ninth term = 89 + 12 = 101
Tenth term = 101 + 12 = 113
Eleventh term = 113 + 12 = 125
Twelfth term = 125 + 12 = 137
Thirteenth term = 137 + 12 = 149
Fourteenth term = 149 + 12 = 161
Fifteenth term = 161 + 12 = 173.
Therefore 15 th term = 173
It is given to find 120 more than the 15 th term. Therefore,
173 + 120 = 293.
So the term's number would be 120 divided by common difference ( d ).
Term = 120 / 12 = 10
So it is the 10 th term after 15th term which is 25 th term.
Hence 293 is the 25 th term of that AP.
Hope this helps !!
Cheers !!
____________________________________________________________
# Kalpesh :)
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