Question

Solve the above equation by factorisation.
Chapter-Quadratic Equations In one Variable​

Answer 1

Answer:

$\huge \boxed a\boxed n \boxed s \boxed w \boxed e \boxed r$

Step-by-step explanation:

$\frac{x}{x + 1} + \frac{x + 1}{x} = \frac{34}{15}$

$\frac{ {x}^{2} + {(x + 1)}^{2} }{x(x + 1)} = \frac{34}{15}$

$\frac{ {x}^{2} + {x}^{2} + 1 + 2x}{ {x}^{2} + x} = \frac{34}{15}$

${15(2x^{2} + 2x + 1)} = 34( {x}^{2} + x)$

$30 {x}^{2} + 30x + 15 = 34 {x}^{2} + 34x$

$0 = 34 {x}^{2} - 30 {x}^{2} + 34x - 30x - 15$

$4 {x}^{2} + 4x - 15 = 0$

$4 {x}^{2} + 10x - 6x - 15 = 0$

$2x(2x + 5) - 3(2x + 5) = 0$

$(2x - 3)(2x + 5) = 0$

$2x - 3 = 0 \: \: or \: \:2x + 5 = 0$

$\huge \red{ x = \frac{3}{2} \: \: or \: \: x = \frac{ - 5}{2} }$