Question

solve the above question..​

Answer 1

$\large{ \sf \: Given}$

$\text{AD \: and \: BC \: are \: equal \: perpendiculars \: to \: a }\: \\ \text{ line \: segment \: AB.}$

$\underline{ \boxed{ \sf \: To \: Prove: CD \: bisects \: AB.}}$

Proof:

In ΔΟAD and ∆OBC

$\text{AD = BC \: \: \green {Given}}$

$\sf \angle OAD = \angle OBC \\ \bold{Each = 90°} \\ \sf {\angle AOD = \angle BOC}$

$\sf \bold{Vertically \: Opposite \: Angles}$

$\sf \: \angle OAD = \triangle OBC \: \bold({ \bold{AAS Rule}}) \:$

OA = OB C.P.C.T.

$\sf \boxed{ \sf \: so \: CD \: bisects \: AB.}$

Answer 2

AD and BC are equal perpendiculars to a

line segment AB.

$\underline{ \boxed{ \sf \: To \: Prove: CD \: bisects \: AB.}} </p><p>\text{AD = BC \: \: \green {Given}}</p><p>\begin{gathered} \sf \angle OAD = \angle OBC \\ \bold{Each = 90°} \\ \sf {\angle AOD = \angle BOC}\end{gathered} </p><p>\sf \bold{Vertically \: Opposite \: Angles}</p><p>\sf \: \angle OAD = \triangle OBC \: \bold({ \bold{AAS Rule}})</p><p>\sf \boxed{ \sf \: so \: CD \: bisects \: AB.}$