Math, asked by StylusMrVirus, 7 months ago

solve the above question..​

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Answered by Anonymous
73

 \large{  \sf \: Given}

 \text{AD  \: and  \: BC  \: are \:  equal \:  perpendiculars  \: to \:  a  }\:  \\ \text{ line \: segment  \: AB.}

 \underline{ \boxed{ \sf \: To  \: Prove: CD  \: bisects  \: AB.}}

Proof:

In ΔΟAD and ∆OBC

 \text{AD = BC \:  \:  \green  {Given}}

  \sf \angle OAD =  \angle OBC \\   \bold{Each = 90°} \\ \sf {\angle AOD =  \angle BOC}

 \sf \bold{Vertically  \: Opposite  \: Angles}

 \sf \: \angle OAD =  \triangle OBC \:   \bold({ \bold{AAS Rule}}) \:

OA = OB C.P.C.T.

 \sf  \boxed{ \sf \: so \: CD  \: bisects  \: AB.}

Answered by Anonymous
91

AD and BC are equal perpendiculars to a

line segment AB.

 \underline{ \boxed{ \sf \: To \: Prove: CD \: bisects \: AB.}}	</p><p>\text{AD = BC \: \: \green {Given}}</p><p>\begin{gathered} \sf \angle OAD = \angle OBC \\ \bold{Each = 90°} \\ \sf {\angle AOD = \angle BOC}\end{gathered} </p><p>\sf \bold{Vertically \: Opposite \: Angles}</p><p>\sf \: \angle OAD = \triangle OBC \: \bold({ \bold{AAS Rule}})</p><p>\sf \boxed{ \sf \: so \: CD \: bisects \: AB.}

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