Question

solve the above question
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Answer 1

Answer:

In triangle ADB

(AB)^2=(AD)^2+(BD)^2

(AB)^2 =(BD×CD) + (BD)^2_________(i)

In triangle ADC

(AC)^2 =(AD)^2 +(CD)^2

(AC)^2 =BD × CD+(CD)^2________(ii)

Add (i) and(ii)

(AB)^2 + (AC)^2 =(BD×CD)+(BD)^2+(BD×CD)+(CD)^2

(AB)^2 + (AC)^2 =(BD)^2 + (CD)^2 +(BD×CD) + (BD×CD)

(AB)^2 +(AC)^2 = (BD)^2 +(CD)^2 + 2(BD ×CD)

( AB)^2 + (AC)^2 = (BD+CD)^2.

{ a^2+b^2+ 2ab =(a+b)^2}

Hence proved