Question

Solve the above two questions

If you can't then don't answer for free points......​

Answer 1

Answer:

⋆ QUESTION ⋆

Q.The sides of a triangle are in the ratio 13:14:15and its perimeter is 84cm. Find the area of the triangle.

Q.The sides of a triangle are 42cm,34cm and 20cm.Calculate its area and the length of the height on the longest side.

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⋆ ANSWER ⋆

Let the sides be 13x, 14x and 15x

Perimeter = Sum of all sides

84 = 13x + 14x + 15x

42x = 84

x = 2

So, the sides are a = 26 cm, b = 28 cm and c = 30 cm

s = p/2 = 84/2 = 42 cm

Area = √s(s - a)(s - b)(s - c)

= √42(42 - 26)(42 - 28)(42 - 30)

= √42×16×14×12

= 4√14×14×36

= 4×14×6

= 336 cm^2

So, area of triangle = 336 cm^2

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2. s = semiperimeter = (42+34+20)/2 = 48 cm

a = 42 cm b = 34 cm c = 20 cm

Area = √[ s (s-a) (s-b) (s-c) ]

= √[ 48 × 6 × 14 × 28 ] cm² = 336 cm²

Altitude on the base of 42 cm = h

336 = 1/2 × 42 × h

h = 16 cm

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hope this will help you~~~⟭⟬