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write the given complex number in the form of a+ib = ( 1 + 3i )^-1
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Answer:
hope it will help you to do this
Step-by-step explanation:
(1−i)
4
=[(1−i)
2
]
2
=[1
2
+i
2
−2i]
2
=[1−1−2i]
2
=(−2i)
2
=(−2i)×(−2i)
=4i
2
=−4,[∵i
2
=−1]
=a+ib, where a=−4, and b=0
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