Question

The center is on the line 8x+5y=0 and the circle passes through the points (2, 1) and (3, 5)

Answer 1

Answer:

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Step-by-step explanation:

Centre lies on the line y−4x+3=0

Let x=h

⇒y=4h−3

So the center is of the form (h,4h−3)

Distance of centre from (2,3) and (4,5) will be equal

⇒(h−2)2+(4h−3−3)2=(h−4)2+(4h−3−5)2⇒h=2

So the centre is (2,5)

r=(2−2)2+(5−3)2=2

So the equation of the circle is 

(x−2)2+(y−5)2=22x2+y2−4x−10y+25=0

Answer 2

Answer:

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