solve the answer plz
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0∫π/2sinx⋅sin2xdx
= 0∫π/2sinx⋅sin2xdx
=2 0∫π/2sin2xcosdx
=20∫π/2 sin2 x⋅d(sinx)
= 32[sin 3x]
x=0
x= 2π
= 32.
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