Question

➡️Solve the attachment !​

Answer 1

The Question must be :

Alpha and beta are two given roots of equation px²+qx+1=0 and find the value of alpha²beta + beta²alpha

Solution :

px²+qx+1 = 0

Here,

a = p

b = q

c = 1

We know that,

alpha+ beta = -b/a = -q/p

alpha × beta = c/a = 1/p

Now,

alpha²beta+beta²alpha

=> taking alpha and beta common,

alpha×beta (alpha+beta)

=> 1/p × (-q/p)

= -q/p² ( required answer )

Answer 2

$\huge\bf{Answer:-}$

Given equation

px² + q + 1 = 0

α + β = 1/a =>> -p/q is the total number of zeros.

αβ = c/a =>> 1/p = product of zeros.

According to the given question we have to find:-

α²β + β²α

αβ.....(α + β)

Adding the values:-

1/p × -q/p

= -q/p²

Therefore, α²β and αβ² => -q/p²

$\huge\bf{Further Explanation:-}$

KNOW MORE:-

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• [α] => alpha and [β] => Beta