Math, asked by Glad05, 1 month ago

solve the attachment​

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Answered by Anonymous
12

\Large{\textsf{\textbf{\underline{\underline{Given\::}}}}} \\

⠀⠀⠀⠀❶ {\textsf{\textbf{x\:+\:2y\:=\:19\:}}} \\

⠀⠀⠀⠀❷ {\textsf{\textbf{x\:+\:3y\:=\:24\:}}} \\

\Large{\textsf{\textbf{\underline{\underline{To\:do\::}}}}} \\

The value of x & y.

\Large{\textsf{\textbf{\underline{\underline{Solution\::}}}}} \\

\dashrightarrow\:\tt{\begin{cases} x\:+\:2y\:=\:19 ---(1) \\ \\ x\:+\:3y\:=\:24 ---(2) \end{cases}\:} \\

Substracting equation (1) from equation (2), we get

\dashrightarrow\:\tt{ x\:+\:3y \: -\: \left( x\:+\:2y\right)\:=\:24\:-\:19\:} \\

\dashrightarrow\:\tt{ x\:+\:3y \: -\: x\:-\:2y\:=\:5\:} \\

\dashrightarrow\:\tt{ 3y \:-\:2y\:=\:5\:} \\

\dashrightarrow\:{\textsf{\textbf{\pink{ y\:=\:5\:}}}} \\

Putting the value of y in equation (1), we get

\dashrightarrow\:\tt{ x\:+\:2\times{5}\:=\:19\:} \\

\dashrightarrow\:\tt{ x\:+\:10\:=\:19\:} \\

\dashrightarrow\:\tt{ x\:=\:19\:-\:10\:} \\

\dashrightarrow\:{\textsf{\textbf{\pink{ x\:=\:9\:}}}} \\

⠀⠀⠀⠀⠀⠀⠀\Large{\textsf{\textbf{\underline{\underline{Verification\::}}}}} \\

Let's play it,

Putting the resulting values of x & y in the equation (2) as,

\dashrightarrow\:\tt{ 9\:+\:3\times{5}\:=\:24\:} \\

\dashrightarrow\:\tt{ 9\:+\:15\:=\:24\:} \\

\dashrightarrow\:\tt{ 24\:=\:24\:} \\

⠀⠀⠀⠀⠀\:\red\star\:\:\bf{\underline{\blue{ Hence\: verified\:}}}\:\:\red\star \\

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