Math, asked by RobinPandey, 1 month ago


Solve the attachment..
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Answered by Athul4152
0

Answer :- 98 + 10√6

 \bf\huge\underline{\underline{ Given :- }}

  • x =  \frac{√3 - √2}{√3+√2} \\

  • y =  \frac{√3 +√2}{√3-√2} \\

 \bf\huge\underline{\underline{ To \: Find:- }}

  • value of + + xy

 \bf\huge\underline{\underline{ Answer :- }}

VALUE OF X

  • x =  \frac{√3 - √2}{√3+√2} \\

  •  \red{\implies}   \frac{(√3 - √2)²}{(√3+√2)(√3-√2)}  \\

  •  \red{\implies}   \frac{3 + 2 - 2√6}{3-2} \\

  •  \red{\implies}   5 - 2√6

VALUE OF Y

  • y =  \frac{√3 + √2}{√3-√2} \\

  •  \red{\implies}  \frac{(√3 + √2)²}{(√3+√2)(√3-√2)} \\

  •  \red{\implies}  \frac{3 + 2 + 2√6 }{3 - 2 } \\

  •  \red{\implies}  5 + 2√6  \\

VALUE OF X² + Y² + XY

  • x² + y² + xy

  •  \red{\implies} (5-2√6)² + (5+2√6)² + 5.2√6

  •  \red{\implies} 25 + 24 - 20√6 + 25 + 24 + 20√6 + 10√6

  •  \red{\implies} 98 + 10√6

 \rule{10cm}{0.05cm}

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