solve the cubis equation xcube-9x+28=0
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chandrakant2:
\begin{lgathered}{x}^{3} - 9x + 28 = 0 \\ x( {x}^{2} - {3}^{2} ) = - 28 \\ x( x - 3)(x + 3) = - 28 \\ x = - 28 \: or \\ x - 3 = - 28 \\ x = - 25 \: or \\ x + 3 = - 28 \\ x = - 28 - 3 = - 31\end{lgathered}x3−9x+28=0x(x2−32)=−28x(x−3)(x+3)=−28x=−28orx−3=−28x=−25orx+3=−28x=−28−3=−31
its not possible
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