Math, asked by knirmalanagasai, 1 month ago

solve the D.E. (D³-3D²+3D-1)y=sinx+x³​

Answers

Answered by pk5987961
3

solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-solve the D.E. (D³-3D²+3D-1)y=sinx+x³²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+3D-1)y=sinx+x³solve the D.E. (D³-3D²+solve the D.E. (D³-3D²+3D-1)y=sinx+x³-1)y=sinx+x³

Answered by rijjushaik455
0

Step-by-step explanation:

m^3-3m^2+3m-1=0

the roots are1;1;1;

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