Solve the DE (D^2-3D+2)y = 2 cos (2x+3)+2e^x
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Answered by
14
Answer:
Solution: Given equation is. (D2 + 3D + 5) y = e2x. AE is D2 + 3D + 5 = 0. ∴. D = 3. 9 20. 3. 11. 2. 2. 2 i. - ±. -. - . = ±. ∴. CF = 3. 2. 1. 2. 11. 11 cos sin. 2. 2 x e c. x c x.
Answered by
1
Answer:
Step-by-step explanation:
Auxiliary equation:
C.F. is given by,
Now we will solve for particular integral using known results,
P.I. is given by,
Finally, y = C.F + P.I
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