Solve the distance x of a particle moving in one dimension
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The question is incomplete:
Here is the full question:
The distance x of a particle moving in 1 dimension under the action of a constant force is related to time t by equation t = root over x + 3 where x is in meters and t is in seconds. Find the displacement when it's velocity is zero.
Answer:
t = √x+3
√x = t-3
x = t² - 6t + 9
dx/dt is the velocity
dx/dt = 2t -6
v = 0
2t-6 = 0
which will give us 3 so t = 3
at t = 3
x = 3-3
so there will be 0 displacement.
Here is the full question:
The distance x of a particle moving in 1 dimension under the action of a constant force is related to time t by equation t = root over x + 3 where x is in meters and t is in seconds. Find the displacement when it's velocity is zero.
Answer:
t = √x+3
√x = t-3
x = t² - 6t + 9
dx/dt is the velocity
dx/dt = 2t -6
v = 0
2t-6 = 0
which will give us 3 so t = 3
at t = 3
x = 3-3
so there will be 0 displacement.
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57
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