Question

solve the equation-

1. (3x-1) (x+4)=0
2. (5a+3) (4a+3)=0
3. (x-2) (2x-1)=0
4. (5z-2) (7z+3)=0

Answer 1

1.(3x-1) (x+4)=0
3x2+12x-x-4=0
3x2+11x-4=0

Answer 2

Hey Mate ✌

Here's your answer friend,

1) (3x - 1)(x + 4) = 0

==> 3x² + 12x - x -4 = 0

==> 3x² + 11x - 4

==> 3x² + 12x - x - 4 = 0

==> 3x(x + 4) -1(x + 4) =0

==> (3x - 1)(x + 4) = 0

==> x = 1/3 or x = -4

Now, next ===>

2) (5a + 3)(4a + 3) = 0

==> 20a² + 15a + 12a + 9 = 0

==> 20a² + 27a + 9 = 0

==> 20a² + 15a + 12a + 9 = 0

==> 5a( 4a + 3) + 3(4a + 3) = 0

==> (5a + 3)(4a + 3) = 0

==> a = -3/5 or a = -3/4

Now next ==>


3) (x - 2)(2x - 1) = 0

==> 2x² -x -4x + 2 = 0

==> x(2x -1) -2(2x - 1) = 0

==> (x - 2)(2x - 1) = 0

==> x = 2 or x = 1/2

Now last question ===>

4) (5z - 2)(7z + 3) = 0

==> 35z² + 15z -14z - 6 = 0

==> 35z² + z - 6 = 0

==> 35z² + 15z - 14z - 6 = 0

==> 5z(7z + 3) -2(7z + 3) = 0

==> (5z - 2)(7z + 3) = 0

==> z = 2/5 or z = -3/7

⭐ Hope it helps you ^_^ ⭐