Question

Solve the equation: 2(x-3)^2+3(x-2)(2x-3)=8(x+4)(x-4)-1

Answer 1

value of x = 33+√6977/32. or

x = 33-√6977/32

Answer 2

The value of x is 5.

Step-by-step explanation:

Given : Equation $2(x-3)^2+3(x-2)(2x-3)=8(x+4)(x-4)-1$

To find : Solve the equation ?

Solution :

$2(x-3)^2+3(x-2)(2x-3)=8(x+4)(x-4)-1$

Using identities,

$(a-b)^2=a^2+b^2-2ab$ and $(a+b)(a-b)=a^2-b^2$

$2(x^2+9-6x)+3(2x^2-3x-4x+6)=8(x^2-16)-1$

$2x^2+18-12x+6x^2-9x-12x+18=8x^2-128-1$

$8x^2-33x+36=8x^2-129$

$8x^2-33x+36-8x^2+129=0$

$-33x+165=0$

$33x=165$

$x=\frac{165}{33}$

$x=5$

Therefore, the value of x is 5.

#Learn more

Solve the following equations.2x+144=160

https://brainly.in/question/2359270