Question

Solve the equation. 2=x²-(x+2)(x+3)/7x+1

Answer 1

$2 = \frac{ {x}^{2} - (x + 2)(x + 3) }{7x + 1} \\ 2 = \frac{ {x}^{2} - ( {x}^{2} + 3x + 2x + 6)}{7x + 1} \\ 2 = \frac{ {x}^{2} - {x}^{2} - 3x - 2x - 6 }{7x + 1} \\ 2 = \frac{ - 5x - 6}{7x + 1} \\ 2(7x + 1) = - 5x - 6 \\ 14x + 2 = - 5x - 6 \\ 14x + 5x = - 6 - 2 \\ 19x = - 8 \\ x = - \frac{8 }{19}$