Solve the equation 2x^2+ax-a^2=0 for x
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Using Sri Dharacharya formula x=[-a+/-(a^2-(-4*2*a^2))^1/2]/2*2
x=[-a+/-(9a^2)^1/2]/4
x=[-a+/-3a]/4
When x=[-a+3a]/4
x=a/2
When x=[-a-3a]/4
x=-a
Hence x= a/2 , -a
x=[-a+/-(9a^2)^1/2]/4
x=[-a+/-3a]/4
When x=[-a+3a]/4
x=a/2
When x=[-a-3a]/4
x=-a
Hence x= a/2 , -a
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