Question

Solve the equation 2y+1=y-3 and represent the solution on (a) Number line (b) In the cartesian plane

Answer 1

Given2x+1=x−3

⇒2x−x=−3−1 by transposition

⇒x=−4

∴in the number line x gets the value −4 from 0 to −4 units.

In the cartesian plane the point lies at x−axis ∴ the y−co-ordinate is 0.

Thus the point (−4,0) lies at negative x−axis.

Answer 2

Step-by-step explanation:

Given2x+1=x-3

→ 2x-x=-3-1 by transposition

⇒x=-4

in the number line x gets the value -4 from 0 to

-4 units.

In the cartesian plane the point lies at x-axis .. the y-co-ordinate is 0.

Thus the point (-4,0) lies at negative x-axis.