Math, asked by vidhaanraisingh, 1 year ago

Solve the equation: 3(4f-6) = 8 f- (4f+3)

Answers

Answered by Anonymous
22

Answer :

\sf{f=\dfrac{15}{8}}

Solution :

\sf{3(4f-6)=8f-(4f+3)}

\implies \sf{12f-18=8f-4f-3}

\implies \sf{12f-18=4f-3}

\implies \sf{12f-4f=-3+18}

\implies \sf{8f=15}

\implies \sf{f=\dfrac{15}{8}} ( required answer )

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Answered by AbhijithPrakash
24

Answer:

3\left(4f-6\right)=8f-\left(4f+3\right)\quad :\quad f=\dfrac{15}{8}\quad \left(\mathrm{Decimal}:\quad f=1.875\right)

Step-by-step explanation:

3\left(4f-6\right)=8f-\left(4f+3\right)

\gray{\mathrm{Expand\:}3\left(4f-6\right):\quad 12f-18}

\gray{\mathrm{Expand\:}8f-\left(4f+3\right):\quad 4f-3}

12f-18=4f-3

\mathrm{Subtract\:}4f\mathrm{\:from\:both\:sides}

12f-18-4f=4f-3-4f

\gray{\mathrm{Simplify}}

8f-18=-3

\gray{\mathrm{Add\:}18\mathrm{\:to\:both\:sides}}

8f-18+18=-3+18

\gray{\mathrm{Simplify}}

8f=15

\gray{\mathrm{Divide\:both\:sides\:by\:}8}

\dfrac{8f}{8}=\dfrac{15}{8}

\gray{\mathrm{Simplify}}

f=\dfrac{15}{8}

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