solve the equation ..3×7^x=7×3^x
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16
3 * 7^x = 7 * 3^x
7^x/3^x=7/3 => (7/3)^x=7/3
as bases are equal , we can equate the numerators
Hence we get
x=1
HOPE IT HELPS,
PLEASE MARK AS BRAINLIEST
ALL THE BEST.
7^x/3^x=7/3 => (7/3)^x=7/3
as bases are equal , we can equate the numerators
Hence we get
x=1
HOPE IT HELPS,
PLEASE MARK AS BRAINLIEST
ALL THE BEST.
Answered by
3
3*7^x = 7*3^x
3/7 = 3^x/7^x
3^1/7^1 = 3^x/7^x
1/1 = x/x
x= 1
3/7 = 3^x/7^x
3^1/7^1 = 3^x/7^x
1/1 = x/x
x= 1
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