solve the equation 3 *x^2-5*x+2=0
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3*x^2+5x+2=0
3x^2+3x+2x+2=0
3x(x+1)+2(x+1)=0
(3x+2)(x+1)=0
3x+2=0
x=-2/3
Or
x+1=0x=-1
Hope it helps
3x^2+3x+2x+2=0
3x(x+1)+2(x+1)=0
(3x+2)(x+1)=0
3x+2=0
x=-2/3
Or
x+1=0x=-1
Hope it helps
Answered by
0
Answer:
x= 2/3 or x= 1
Step-by-step explanation:
3x^2- 5x +2
Splitting the middle term,
3x^2 - 3x - 2x + 2,
split the middle term in such a way that on adding you get the middle term but on multiplying you get the answer of product of first (3x^2) and third term (2).
3x (x-1) - 2 (x-1) = 0
(3x-2) ( x-1) = 0
3x-2 = 0 or x-1 = 0
x= 2/3 or x= 1
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