Question

solve the equation 3x2-4x+20/3=0​

Answer 1

Step-by-step explanation:

$3 {x}^{2} - 4x + \dfrac{20}{3} = 0 \\ multiplying \: by \: 3 \: in \: whole \: equation \\ 9 {x}^{2} - 12x + 20 = 0 \\ comparing \: it \: with \: \: \\ a {x}^{2} + bx + c = 0 \\ a = 9 \: \\ b = - 12 \: \\ c = 20 \\ {b}^{2} - 4ac = {( - 12)}^{2} - 4(9) \: (20) \\ = 144 - 720 \\ = - 576 < 0 \\ so \: no \: real \: value \: of \: x \: satisfy \: the \: equation$