solve the equation 4√3x²+5x–2√3=0
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4√3x^2+8x-3x-2√3=0
=2x(√3x+1)-√3(√3x+1)=0
=(2x-√3)(√3x+1)=0
=if 2x-√3=0
the x=√3/2
if √3x+1=0
then x=1/√3
=2x(√3x+1)-√3(√3x+1)=0
=(2x-√3)(√3x+1)=0
=if 2x-√3=0
the x=√3/2
if √3x+1=0
then x=1/√3
onlinewithmahesh:
Hi
Ur answer is wrong
Pls see mine answer for the correct answer.
typing and solving maths in mobile is difficult. I did the simplest quetion wrong.
Answered by
6
4√3 x² +5x -2√3 =0
⇒4√3 x² +8x -3x -2√3=0
⇒4x(√3 x+2) -√3(√3x +2) =0
⇒(√3x +2)(4x -√3) =0
⇒(√3x +2) =0 or (4x-√3) =0
⇒x = -2/√3 or √3/4
Is your answer right?
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