solve the equation 4x^2-5x-3=0
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Answered by
1
first we find value of delta
∆=b²-4ac
= (-5)²-4(4)(-3)
= 25+48
=73
x=( -b±√∆)/2a
=( 5±√73)/8
x= 5/8+√73/8 or 5/8-√73/8
∆=b²-4ac
= (-5)²-4(4)(-3)
= 25+48
=73
x=( -b±√∆)/2a
=( 5±√73)/8
x= 5/8+√73/8 or 5/8-√73/8
Answered by
0
x=5+-√73/8 are required roots
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