Question

Solve the equation 5 sinθ – 2 cos^2θ – 1 = 0

Answer 1

Answer:

Given, 5 sinθ – 2 cos^2θ – 1 = 0  

or,5 sinθ – 2 (1 – sin^2θ) – 1 = 0  

or,2 sin^2 θ + 5 sin θ – 3 = 0  

or,(sin θ + 3) (2 sin θ – 1) = 0  

∴sin θ = 3 or, sin θ = 1/2  

if sin θ = 3

This is not possible as range of sine is [–1, 1]    

If sin θ = 1/2                                  

or, sin θ = sin π/6  

⇒ θ = n π + (–1)^n π/6  

where n = 0, ±1, ±2 ……  

hope it will help you

Thanks for asking

Answer 2

Answer:

thanks for asking stay blessed yaar

Step-by-step explanation:

15/√2 × 10–5