solve the equation
5x+7/2=3/2x-14
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Given equation :
Given equation :5x + 7/2 = 3x/2 – 14
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of the
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)=> x = (-35 × 2)/(2×7)
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)=> x = (-35 × 2)/(2×7)After cancellation, we get
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)=> x = (-35 × 2)/(2×7)After cancellation, we get=>x=-5
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)=> x = (-35 × 2)/(2×7)After cancellation, we get=>x=-5Therefore,
Given equation :5x + 7/2 = 3x/2 – 14Subtract 7/2both sides of theequation, we get=> 5x+7/2-7/2=3x/2-14-7/2=>5x -3x/2=-14 – 7/2=> (10x-3x)/2 = (-28-7)/2=> 7x/2 = -35/2=> x = (-35/2) × (2/7)=> x = (-35 × 2)/(2×7)After cancellation, we get=>x=-5Therefore,x=-5
Step-by-step explanation: