Question

Solve the equation 9x² + 6x - 35 = 0 using the method of completing a square.​

Answer 1

Answer:

What is meant by completing a square

Answer 2

Answer:

$\huge\fbox{Answer ☘}$

$9x {}^{2} + 6x - 35 = 0 \\ \\ = > x {}^{2} + \frac{6x}{9} - \frac{35}{9} = 0 \\ \\ = > x {}^{2} + \frac{2x}{3} - \frac{35}{9} = 0 \\ \\ x {}^{2} + \frac{2x}{3} + ( \frac{1}{3} ) {}^{2} - ( \frac{1}{2} ) {}^{2} - \frac{35}{9} = 0 \\ \\ (x + \frac{1}{3}) {}^{2} - \frac{1}{9} - \frac{35}{9} = 0 \\ \\ (x + \frac{1}{3} ) {}^{2} - \frac{36}{9} = 0 \\ \\ (x 7+ \frac{1}{3} ) {}^{2} - 4 = 0 \\ \\ (x + \frac{1}{3} ) {}^{2} - 2 {}^{2} = 0$

hope helpful~