Question

Solve the equation :
ax + by = 0
bx + ay = 1 + c​

Answer 1

Answer:

x=b+bc/b^2-a^2, y=a(1+c) /b^2-a^2

Step-by-step explanation:

first we consider ax+by=0......equation 1

then bx+ay=1+c

=bx+ay-c=1.....equation2

from equation 1, y=-ax/b

put value of y in equation 2,we get

bx-a^2x-c=1

=b^2x-a^2x-bc=b (by using L.C.M)

=x=b+bc/b^2-a^2

again,value of x putting in y=-ax/b, we

get y=a(1+c) /b^2-a^2