Question

Solve the equation by factorisation method

${n}^{2} + 301n - 3110 = 0$
​

Answer 1

Answer:

n=10

Step-by-step explanation:

n²+301n-3110=0

n²+311n-10n-3110=0

n(n+311)-10(n+311)=0

(n+311)(n-10)=0

n=-311/n=10

Therefore, n=10

Please mark it the brainliest answer if it helps you.

Answer 2

solutions is attached above ..... ....