solve the equation by substitution and elimination method 11x+15y+23=0 and 7x-2y-20=0
Answers
Step-by-step explanation:
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Given :
- 11x + 15y + 23 = 0
- 7x - 2y - 20 = 0
To Find :
Find the Value of x and y
Solution:
By Elimination method :-
→ [ 11x + 15y = -23 ] × 2
[ 7x - 2y = 20 ] × 15
→ 22x + 30y = -46
105x - 30y = 300
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→ 127x = 254
→ x = 2
Now, Substituting the value of x on 7x - 2y = 20, we get :
→ 7(2) - 2y = 20
→ 2y = 14 - 20
→ 2y = -6
→ y = -3
Hence,
Hence,The value of x is 2 and y is -3
By substitution method :-
→ 7x - 2y = 20
→ y = 7x - 20/2
Now,
Substituting the value of y on 11x + 15y = -23, we get :
→ 11x + 15(7x - 20/2) = -23
→ 11x + 105x - 300/2 = -23
→ 22x + 105x - 300/2 = -23
→ 127x - 300 = -46
→ 127x = 300 - 46
→ 127x = 254
→ x = 2
Now, Substituting the value of x on y = 7x - 20/2, we get :
→ y = 7(2) - 20/2
→ 14 - 20/2
→ -6/2
→ -3
Hence,
Hence, The value of x is 2 and y is -3.