Math, asked by vijaytharani2005, 9 months ago

solve the equation by substitution and elimination method 11x+15y+23=0 and 7x-2y-20=0​

Answers

Answered by ved2k4
4

Step-by-step explanation:

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Answered by Anonymous
9

Given :

  • 11x + 15y + 23 = 0

  • 7x - 2y - 20 = 0

To Find :

Find the Value of x and y

Solution:

By Elimination method :-

→ [ 11x + 15y = -23 ] × 2

[ 7x - 2y = 20 ] × 15

→ 22x + 30y = -46

105x - 30y = 300

__________________

→ 127x = 254

→ x = 2

Now, Substituting the value of x on 7x - 2y = 20, we get :

→ 7(2) - 2y = 20

→ 2y = 14 - 20

→ 2y = -6

→ y = -3

Hence,

Hence,The value of x is 2 and y is -3

By substitution method :-

→ 7x - 2y = 20

→ y = 7x - 20/2

Now,

Substituting the value of y on 11x + 15y = -23, we get :

→ 11x + 15(7x - 20/2) = -23

→ 11x + 105x - 300/2 = -23

→ 22x + 105x - 300/2 = -23

→ 127x - 300 = -46

→ 127x = 300 - 46

→ 127x = 254

→ x = 2

Now, Substituting the value of x on y = 7x - 20/2, we get :

→ y = 7(2) - 20/2

→ 14 - 20/2

→ -6/2

→ -3

Hence,

Hence, The value of x is 2 and y is -3.

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