Question

Solve the equation by trial and error method....

$z - 3 = 2z - 5$
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Answer 1

Answer:

z−3=2z−5

At z=0, LHS=0−3=−3, RHS=0−5=−5

LHS



=RHS

At z=1, LHS=1−3=−2, RHS=2(1)−5=−3

LHS



=RHS

At z=2, LHS=2−3=−1, RHS=2(2)−5=−1

LHS=RHS

∴z=2 is the root

Answer 2

Answer:

z-3=2z-5

2z-z=-5+3

z=-2