Solve the equation by using completing square method: x^2 +4x +5 = 0. Explain every step.
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Step 1.)
Transfer the constant term in RHS
=> x^2 + 4x = - 5
Step 2.)
Divide the equation by the coficient of x^2
=> x^2 + 4x = - 5
Step 3.)
Add square of half of the coficient of x in both sides
=> x^2 + 4x + (2)^2 = - 5 + (2)^2
=> ( x + 2)^2 = ( - 5 + 4)
=> ( x + 2) = sqrt ( - 1)
=> x + 2 = + - i
=> x = - 2 +- i
Roots are - 2 + i and - 2 - i
Transfer the constant term in RHS
=> x^2 + 4x = - 5
Step 2.)
Divide the equation by the coficient of x^2
=> x^2 + 4x = - 5
Step 3.)
Add square of half of the coficient of x in both sides
=> x^2 + 4x + (2)^2 = - 5 + (2)^2
=> ( x + 2)^2 = ( - 5 + 4)
=> ( x + 2) = sqrt ( - 1)
=> x + 2 = + - i
=> x = - 2 +- i
Roots are - 2 + i and - 2 - i
MERCURY1234:
bro answer my question
Answered by
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HERE :
A = 1
B = 4
C = 5
USING QUADRATIC EQUATION, WE GET
X = - b + √b^2 -4ac/2a
X = - 4 + √4^2 - 4×1×5/2×1
X = - 4 + √16 - 20/2
X = - 4 + √-4/2
X = - 4 + √4 × i^2/2
X = - 4 + √4 × √i^2/2
X = - 4 + 2 × i/2
X = - 4 + 2i/2
X = - 4 + or - 2i/2
A = 1
B = 4
C = 5
USING QUADRATIC EQUATION, WE GET
X = - b + √b^2 -4ac/2a
X = - 4 + √4^2 - 4×1×5/2×1
X = - 4 + √16 - 20/2
X = - 4 + √-4/2
X = - 4 + √4 × i^2/2
X = - 4 + √4 × √i^2/2
X = - 4 + 2 × i/2
X = - 4 + 2i/2
X = - 4 + or - 2i/2
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