solve the equation hy substituting method:. 3x+2y=2 & 2x-5y-1=0
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3x + 2y = 2 ----------------- [ 1 ]
2x - 5y - 1 = 0 --------------- [ 2 ]
From [ 1 ]:
3x + 2y = 2
3x = 2 - 2y
x = 2/3 - 2/3 y --------------- Sub into equation [ 2 ]
2x - 5y - 1 = 0
2( 2/3 - 2/3 y) - 5y - 1 = 0
4/3 - 4/3 y - 5y - 1 = 0
1/3 - 19/3y = 0
19/3 y = 1/3
19y = 1
y = 1/19 --------------- Sub into equation [ 1 ]
3x + 2y = 2
3x + 2(1/19) = 2
3x + 2/19 = 2
3x = 2 - 2/19
3x = 36/19
x = 12/19
Answer: x = 12/19 and y = 1/19
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