Solve the equation: Log 2t3 – Log t = Log 16 + Log t.
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Step-by-step explanation:
Log(2t³) - Log(t) = Log(16) + Log(t) → where: t > 0
Log(2t³) - Log(t) = Log(16) + Log(t) → you know that: Log(ab) = Log(a) + Log(b)
Log(2) + Log(t³) - Log(t) = Log(16) + Log(t) → you know that: Log(x^a) = a.Log(x)
Log(2) + 3.Log(t) - Log(t) = Log(16) + Log(t)
Log(2) + Log(t) = Log(16)
Log(t) = Log(16) - Log(2) → you know that: Log(a) - Log(b) = Log(a/b)
Log(t) = Log(16/2)
Log(t) = Log(8)
t = 8
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