Solve the equation log2(5x+3)=log2(2x+1)for x
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Answer:
log(5x+3) base 2 = log(2x+1) base 2
=> both have same base so compare the values of log.
=> 5x+3 = 2x+1
=> 5x-2x = 1-3
=> 3x = -2
=> x = -2/3
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