Question

solve the equation (m - 3) x² - 4x + 1 = 0​

Answer 1

Answer:4/2m-6±√28-4m/2m-6

Step-by-step explanation:

Answer 2

$\huge\bold \red{Answer}$

(m-3)x^2-4x+1=0

here a=(m-3) , b=-4 , c=1

x=(-b+root b^2-4ac)/2a or (-b- root b^2-4ac)/2a

x=[4+root 16-4(m-3)]/2(m-3) or

[4-root 16 -4(m-3)]/2(m-3)