solve the equation Q2. 7z - 18 = 2 - 28 + 2z
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Q2) 7z - 18 = 2 - 28 + 2z
=> 7z - 2z = 2- 28 +18
=> 5z = 20 -28
=> 5z = -8
=> z = -8/5
Now,
verify the equation:-
=>7z - 18 = 2 - 28 + 2z
=> 7(-8/5) - 18 = 2 - 28 + 2(-8/5)
=> -56/5 - 18 = - 26 - 16/5
=> -56 -90/5 = -130-16/5
=> -146/5 = -146/5
LHS = RHS
Linear equation in one variable :- it is an equation which is formed in the az + b = 0 where, A and B are two integers and z is only one variable so, it has only one solution.
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