Question

solve the equation : root over x/1-x + root over x-1/x = 2 to the power of 1/6 (x is not equal to 0,1)

Answer 1

Answer:

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Answer 2

Answer:

$\sqrt{ \frac{x}{1 - x} } + \sqrt{ \frac{x - 1}{x} } =2 \\ \\ \\ \\ \\ = > \sqrt{ \frac{x}{ 1 - x} + \frac{x - 1}{x} } = 2 \\ \\ \\ = > \frac{x}{ 1 - x} + \frac{x - 1}{x} = 4 \\ \\ = > {x}^{2} + ( {1 - x})^{2} = 4x(1 - x) \\ \\ \\ = > {x}^{2} + 1 + {x}^{2} - 2x = 4x - {4x}^{2} \\ \\ = > 6 {x}^{2} - 2x + 1 = 0$

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