Question

solve the
equation.
sina.cosa+cosa.sina​

Answer 1

Answer:

Step-by-step explanation:

Given:  \frac{\cos A +\sin A}{\cos A -\sin A}- \frac{\cos A -\sin A}{\cos A +\sin A}= 2\tan 2A

Explanation:

\frac{\cos A +\sin A}{\cos A -\sin A}- \frac{\cos A -\sin A}{\cos A +\sin A}= 2\tan 2A

\\\\\cos 2x =\cos^2 x-\sin^2x \\\\\text{taking LCM}\\\\\frac{\cos^2A+\sin^2A+2\cosA\sinA- (\cos^2A+\sin^2A-2\cosA\sinA)}{\cos 2 A}\\\\\frac{\sin 2A+\sin 2A}{\cos 2 A}\\\\\frac{2\sin 2 A}{\cos 2 A}\\\\= 2\tan2A

hence proved

Answer 2

Answer:

2sina.cosa

Step-by-step explanation:

Sina.cosa +cosa.sina

= sina.cosa+sina.cosa

=2sina.cosa