Question

Solve the equation:
$\frac{4x-3}{2x+3}$=$\frac{5}{7}$

Also Verify the answer.​

Answer 1

Explanation:

$\huge\fcolorbox{blue}{green}{Solution}$

• 7 (4x - 3) = 5 (2x + 3)

• (28x - 21) = (10x + 15)

• 28x - 21 = 10x + 15

• 28x - 10x = 15 + 21

• 18x = 36

• x = 36/18

• x = 3

$\huge\fcolorbox{blue}{green}{Check LHS}$

• 4 * 3 - 3 = 9

$\huge\fcolorbox{blue}{green}{Check RHS}$

• 2 * 3 + 3 = 9

$\huge\fcolorbox{blue}{green}{Hence Verifed}$

$\huge\fcolorbox{black}{yello}{LHS = RHS}$

Answer 2

$\sf\red{Equation\:given:-}$

$↠\dfrac{4x-3}{2x+3}$=$\dfrac{5}{7}$

What to do:-

• To solve the given equation.
• And to verify the ans.

$\sf\blue{Solution:}$

By multiplying both the sides of the equation by (2x+3)

$↠\rm\dfrac</p><p>{4x-3}{2x+3}×(2x+3)$=$\rm\dfrac{5}{7}×(2x+3)$

$\rm{↠4x-3}=$$\rm\dfrac{5}{7}×$(2x+3)

Since,the denominator of R.H.S is 7.

•Multiply both the sides by 7

$↠\rm{4x-3}×7=7×\dfrac{5}{7}×(2x+3)$

$\rm{↠28x-21=5(2x+3)}$

$\rm{↠28x-21=10x+15}$

$\rm{↠28x-10x=15+21}$

$\rm{↠18x=36}$

$\rm{↠x}=\dfrac{36}{18}=2$

Therefore,the value of x=2.

$\sf\green{Verification:}$

L.H.S.= $\dfrac{4x-3}{2x+3}$

R.H.S.= $\dfrac{5}{7}$

Let's ,put the value of x in L.H.S.

$\leadsto\dfrac{4x-3}{2x+3}$

$\leadsto\dfrac{4×2-3}{2×2+3}$

$\leadsto\dfrac{8-3}{4+3}$

$\leadsto\dfrac{5}{7}$

Hence,L.H.S = R.H.S.

Therefore, Verified.