Math, asked by bpnboruah, 7 hours ago

solve the equation (using method of your choice) 2x+y=7 ; 3x+2y=11​

Answers

Answered by Anonymous
56

Your answer is in the attachment hope it helps :)

Attachments:
Answered by Khushi20993
14

Answer:

Solution -

Consider the equations -

2x + y = 7 ___ (1)

3x + 2y = 11 ___ (2)

In a first way, multiply equation (1) by 3 and equation (2) by 2, we get,

6x + 3y = 21 ___ (3)

6x + 4y = 22 ___ (4)

Finally, subtract equation (4) from equation (3). We get-

6x + 21y – 6x – 2y = 30 – 12

⇒ 19y = 18

y = 18/19

In order to get the value of x, the value of y is substituted in equation (2),

3x + 18/19 =

3x = 6 – 18/19

3x = 96/19

x = 96/57 = 32/19

Alternatively, multiply equation (2) with 7,

21x + 7y = 42 _____ (5)

And equation (1) is

2x + 7y = 10

Subtracting equation (1) from equation (5), we get

19x = 32

x = 32/19

Substituting the value of x in Eqn. (1),

2(32/19) + 7y = 10

7y = 10 – 64/19

7y = 126/19

y = 18/19

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