solve the equation (using method of your choice) 2x+y=7 ; 3x+2y=11
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Solution -
Consider the equations -
2x + y = 7 ___ (1)
3x + 2y = 11 ___ (2)
In a first way, multiply equation (1) by 3 and equation (2) by 2, we get,
6x + 3y = 21 ___ (3)
6x + 4y = 22 ___ (4)
Finally, subtract equation (4) from equation (3). We get-
6x + 21y – 6x – 2y = 30 – 12
⇒ 19y = 18
y = 18/19
In order to get the value of x, the value of y is substituted in equation (2),
3x + 18/19 =
3x = 6 – 18/19
3x = 96/19
x = 96/57 = 32/19
Alternatively, multiply equation (2) with 7,
21x + 7y = 42 _____ (5)
And equation (1) is
2x + 7y = 10
Subtracting equation (1) from equation (5), we get
19x = 32
x = 32/19
Substituting the value of x in Eqn. (1),
2(32/19) + 7y = 10
7y = 10 – 64/19
7y = 126/19
y = 18/19
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