solve the equation: x^2+3x+5=0
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Answer:
=
−
±
2
−
4
√
2
x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}
x=2a−b±b2−4ac
Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.
2
+
3
+
5
=
0
x^{2}+3x+5=0
x2+3x+5=0
=
1
a={\color{#c92786}{1}}
a=1
=
3
b={\color{#e8710a}{3}}
b=3
=
5
c={\color{#129eaf}{5}}
c=5
=
−
3
±
3
2
−
4
⋅
1
⋅
5
Step-by-step explanation:
i hope it will help you
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