Math, asked by smitaagarwal52, 8 hours ago

solve the equation: x^2+3x+5=0

Answers

Answered by apekshasrivastava070
0

Answer:

=

±

2

4

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

2

+

3

+

5

=

0

x^{2}+3x+5=0

x2+3x+5=0

=

1

a={\color{#c92786}{1}}

a=1

=

3

b={\color{#e8710a}{3}}

b=3

=

5

c={\color{#129eaf}{5}}

c=5

=

3

±

3

2

4

1

5

Step-by-step explanation:

i hope it will help you

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