solve the equation (x-2)^.
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Answered by
1
if there is no power its power is 2 so....
(a-b)²=a²+b²-2ab
(a-b)²=a²+b²-2ab
Answered by
3
I think you want to ask solve the equation (x-2)^2.If it is your question then here your answer-
We know that (a-b) ^2 = a^2 + b^2 - 2ab
Now,
(x-2)^2= x^2 + 2^2 - 2*x*2
=x^2 - 4x + 4=0
=x^2 - 2x - 2x +4=0
=x(x-2)-2(x-2)=0
=(x-2)(x-2)=0
So x=2
We know that (a-b) ^2 = a^2 + b^2 - 2ab
Now,
(x-2)^2= x^2 + 2^2 - 2*x*2
=x^2 - 4x + 4=0
=x^2 - 2x - 2x +4=0
=x(x-2)-2(x-2)=0
=(x-2)(x-2)=0
So x=2
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