Question

solve the equation x^+2x -3= 0 using the formula​

Answer 1

Answer:

$•°• \: {x}^{2} + 2x - 3 = (x + 3)(x - 1)$

Step-by-step explanation:

$= {x}^{2} + 2x - 3$

$= {x}^{2} + 3x - x - 3$

$= x(x + 3) - 1(x + 3)$

$= (x + 3)(x - 1)$

Adiós! Hope this helps you.

Answer 2

Step-by-step explanation:

x^2+2x-3=0

a=1,b=2,c= -3

$= ( - b \frac{ + }{ - } \sqrt{b {}^{2} - 4ac } ) \div 2a$

$( - 2 \frac{ + }{ - } \sqrt{4 - 4 \times ( - 3)} ) \div 2 \times 1$

$( - 2 \frac{ + }{ - } \sqrt{16}) \div 2$

$- 1 + 2 \: \: \: \: \: \: or \: \: \: \: \: - 1 - 2$

$1 \: \: or \: \: \: \: - 3$