solve the equation x²+4x-7=0
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Answer: x²+4x-7=0
=>x²+(2×x×2)+2²-2²-7=0 (Completing the square)
=>(x+2)²=7+4=11
=>x+2=+/-(11)^1/2
=>x=-2+/-(11)^1/2
=>x= -{2+(11)^1/2} or x= (11)^1/2-2
I hope my ans helps
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